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Home/ Questions/Q 8974409
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T18:40:25+00:00 2026-06-15T18:40:25+00:00

I am using the following classes declaration: class A { public: A(int, float); A(const

  • 0

I am using the following classes declaration:

class A {
public:
    A(int, float);
    A(const A&);
};

class B {
public:
    B(A&);
protected:
    A a;
};

I also set up the following definition for B:

B::B(A &a) {
    this->a = a;
}

The problem is I have an error on the definition of my Bconstructor, telling me that there is No matching function for call to A::A().

Why does my B constructor tries to create a new A?

If the previous step is needed, why doesn’t it call the copy constructor using the reference?

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  1. Editorial Team
    Editorial Team
    2026-06-15T18:40:27+00:00Added an answer on June 15, 2026 at 6:40 pm

    I assume your B has an A that needs to be constructed. In your current constructor, your not explicitely specifying an A constructor to use. Therefore it tries the default constructor of A which does not exist:

    Maybe you meant to construct B’s A with the reference?

    class B {
    private:
        A _a;
    public:
        B(A& a) : _a(a) {}
    
    };
    
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