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Home/ Questions/Q 6330225
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:49:59+00:00 2026-05-24T17:49:59+00:00

I am using the following code: function deleteImage2($item) { $item.fadeOut(function() { var $list =

  • 0

I am using the following code:

function deleteImage2($item)
{
    $item.fadeOut(function()
    {
        var $list = $('ul',$albumcover).length ? $('ul',$albumcover) : $('<ul class="gallery ui-helper-reset"/>').appendTo($albumcover);
        $item.appendTo($list).fadeIn();
    });
}

“albumcover” is name of DIV and this code is working fine, but I need to append last node, how can I modify this query?

Kind Regards

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T17:50:00+00:00Added an answer on May 24, 2026 at 5:50 pm
    function deleteImage2($item)
    {
        $item.fadeOut(function()
        {
            var $list = ($('ul',$albumcover).length ? $('ul:last',$albumcover) : $('<ul class="gallery ui-helper-reset"/>')).appendTo($albumcover);
            $item.appendTo($list).fadeIn();
        });
    }
    

    add :last in your selector to select only last item

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