Question

I am using the following code in my Cocoa project to call a script I made. The script is in the same folder as the project and even shows up under the “Resources” folder in Xcode. The proper path is found, but it still says that the path is not accessible. Help please.

NSBundle *mainBundle=[NSBundle mainBundle];
NSString *path=[mainBundle pathForResource:@"script" ofType:@"sh"];

NSTask *task = [[NSTask alloc] init];
[task setLaunchPath: path];

NSLog (path);

NSPipe *pipe = [NSPipe pipe];
[task setStandardOutput: pipe];
[task setStandardError: pipe];

NSFileHandle *file = [pipe fileHandleForReading];

[task launch];
[task waitUntilExit];

NSData *data = [ddFile readDataToEndOfFile];

NSString *output = [[NSString alloc] initWithData: data encoding: NSUTF8StringEncoding];

NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterDecimalStyle];
HDSpeed = [f output];

[f release];    
[task release];

The output I get in the debugger is:

2010-07-10 17:53:26.384 tester[5023:a0f] /Users/guest/Library/Developer/Xcode/DerivedData/tester-bhukztmqjwoqrwereagsshvtbfqx/Build/Products/Debug/tester.app/Contents/Resources/script.sh

2010-07-10 17:53:26.386 tester[5023:a0f] launch path not accessible

Answer 1

What you will need to do is get the shell binary, and pass your script as an argument. So if the shell script is written targeting bash, get the bash interpreter, and pass it an argument list with one argument: the path to your script.sh.