Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 799353
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T23:06:44+00:00 2026-05-14T23:06:44+00:00

I am using the following code to capture all the AJAX calls being made

  • 0

I am using the following code to capture all the AJAX calls being made from my app, in order to show a busy spinner till the call is completed. It works well when the requests are well spaced out. However, when the request are made in quick successions, some of the AJAX calls do not get registered, or the onCreate and onComplete actions get kicked off at the same time, and more often than not, the busy spinner continues to appear on the screen, after all the calls have successfully completed. Is there any check I can perform at the end of the call, to check if the element is visible, I can hide it.

document.observe("dom:loaded", function() {
$('loading').hide(); 
Ajax.Responders.register({
//When an Ajax call is made. 
onCreate: function() {
new Effect.toggle('loading', 'appear');
new Effect.Opacity('display-area', { from: 1.0, to: 0.3, duration: 0.7 });
},

onComplete: function() {
new Effect.toggle('loading', 'appear');
new Effect.Opacity('display-area', { from: 0.3, to: 1, duration: 0.7 });
}
});
});

Thanks!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T23:06:44+00:00Added an answer on May 14, 2026 at 11:06 pm

    You need to keep a count of how many AJAX requests are processing, and only hide the loading indicator if no further requests are processing.

    Try code similar to the following:

    document.observe("dom:loaded", function() {
    
      var ajaxRequestsInProgress = 0;
    
      $('loading').hide(); 
    
      Ajax.Responders.register({
        //When an Ajax call is made. 
        onCreate: function() {
          if(!ajaxRequestsInProgress)
          {
            new Effect.toggle('loading', 'appear');
            new Effect.Opacity('display-area', { from: 1.0, to: 0.3, duration: 0.7 });
          }
          ajaxRequestsInProgress++;
        },
    
         onComplete: function() {
           ajaxRequestsInProgress--;
           if(!ajaxRequestsInProgress)
           {
             new Effect.toggle('loading', 'appear');
             new Effect.Opacity('display-area', { from: 0.3, to: 1, duration: 0.7 });
           }
         }
      });
    });
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm using the following piece of code to login a user via Ajax. //Capture
I have the following code to display an image in imagebox using EmgucV: Capture
I am using following code to show a spinning wheel: $(#loading) .hide() .ajaxStart(function(){ $(this).show();
I am using following code to get bitmap from url. This function is used
I am using the following code to capture video and save it to the
I'm using the following code to capture a screenshot of the selected tab chrome.tabs.captureVisibleTab(
I am using the following code to capture change text in HTML inputs: $(document).ready(function()
Using following code I try to get updated list of checkbuttons' corresponding text values,
I using following code: var search = 'test'; if ($('#sku').find(search) ){ //alert(search); $(document).find(search).css('color','red'); <TABLE>
I am creating date using following code try { newdatetime = new DateTime(2012, 2,

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.