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Home/ Questions/Q 3215912
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T15:13:59+00:00 2026-05-17T15:13:59+00:00

I am using the following code to compare types so that a DataContractSerializer will

  • 0

I am using the following code to compare types so that a DataContractSerializer will re-initialize with the correct type if necessary.

    private void InitializeSerializer(Type type)
    {
        if (this.serializer == null)
        {
            this.serializer = new DataContractSerializer(type);
            this.typeToSerialize = type;
        }
        else
        {
            if (this.typeToSerialize != null)
            {
                if (this.typeToSerialize.GetType() != type.GetType())
                {
                    this.serializer = new DataContractSerializer(type);
                    this.typeToSerialize = type;
                }
            }
        }
    }

For some reason when I compare the two types the result is always true and I never enter the final ‘if’ statement and re-initialize my serialiser.

I can set a break point at the comparison and clearly see that the two types are
List<Host> (this.typeToSerialize.GetType()) and
Post (type.GetType())

Both Host and Post share a common ancestor but that shouldn’t be affecting the result.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T15:14:00+00:00Added an answer on May 17, 2026 at 3:14 pm

    You are calling GetType() on a System.Type. This will return a System.Type object that describes System.Type itself.

    This makes the code

    if (this.typeToSerialize.GetType() != type.GetType())
    {
       ...
    }
    

    equivalent to:

    if(typeof(System.Type) != typeof(System.Type)) // Always false
    {
       ... // Never enters here
    }
    

    I’m guessing what you really mean to be doing is:

    if(typeToSerialize != type)
    {
       ...
    }
    
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