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Home/ Questions/Q 9209307
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T00:48:44+00:00 2026-06-18T00:48:44+00:00

I am using the following code to throw an error if the size of

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I am using the following code to throw an error if the size of vector (declared as vector<int> vectorX) is is different than intended.

vector<int> vectorX;
int intendedSize = 10;
// Some stuff here
if((int)(vectorX.size()) != (intendedSize)) {
    cout << "\n Error! mismatch between vectorX "<<vectorX.size()<<" and intendedSize "<<intendedSize;
    exit(1);
}

The cout statement shows the same size for both. The comparison is not showing them to be equal.

Output is Error! mismatch between vectorX 10 and intendedSize 10

Where is the error? Earlier I tried (unsigned int)(intendedSize) but that too showed them unequal.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T00:48:45+00:00Added an answer on June 18, 2026 at 12:48 am

    You are missing ) in the right side of if statement

    if((int)(vectorX.size()) != (intendedSize)) {
                                              ^^^
    }
    

    But note, it’s bad to cast return value of std::vector::size to int. You lose half of the possibilities of what the size could be(thanks to chris).

    You should write:

    size_t intendedSize = 10; 
    // OR unsign int intendedSize  = 10; 
    if(vectorX.size() != intendedSize) {
    }
    
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