Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 81413
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 10, 20262026-05-10T21:27:22+00:00 2026-05-10T21:27:22+00:00

I am using the following jquery code: $(#top ul li.corner).mouseover(function(){ $(span.left-corner).addClass(left-corner-hover); $(span.right-corner).addClass(right-corner-hover); $(span.content).addClass(content-hover); }).mouseout(function(){

  • 0

I am using the following jquery code:

$('#top ul li.corner').mouseover(function(){     $('span.left-corner').addClass('left-corner-hover');     $('span.right-corner').addClass('right-corner-hover');     $('span.content').addClass('content-hover'); }).mouseout(function(){     $('span.left-corner').removeClass('left-corner-hover');     $('span.right-corner').removeClass('right-corner-hover');     $('span.content').removeClass('content-hover');  }); 

But as you see in the selector that is going to do every li.corner that the mouse is over. i am trying to get it to do only the one the mouse is over, how would I achieve that?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-10T21:27:22+00:00Added an answer on May 10, 2026 at 9:27 pm

    i tried to approximate what i imagined your code would look like, and the test runs fine:

    css:

    .left-corner-hover, .right-corner-hover, .content-hover {     background-color: #CCC; } 

    jQuery:

    $('#top ul li.corner').mouseover(function(){     $('span.left-corner', this).addClass('left-corner-hover');     $('span.right-corner', this).addClass('right-corner-hover');     $('span.content', this).addClass('content-hover'); }).mouseout(function(){     $('span.left-corner', this).removeClass('left-corner-hover');     $('span.right-corner', this).removeClass('right-corner-hover');     $('span.content', this).removeClass('content-hover');  }); 

    html:

    <div id='top'>     <ul>         <li class='corner'>             <span class='left-corner'>Left Corner</span>             <span class='content'>Content</span>             <span class='right-corner'>Right Corner</span>         </li>     </ul>     <ul>         <li class='corner'>             <span class='left-corner'>Left Corner</span>             <span class='content'>Content</span>             <span class='right-corner'>Right Corner</span>         </li>     </ul> <div> 
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 144k
  • Answers 144k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer I'd use the OutOfRangeException only when working with arrays /… May 12, 2026 at 8:41 am
  • Editorial Team
    Editorial Team added an answer SimpleHtmlDom example (isn't it pretty?): // Create DOM from URL… May 12, 2026 at 8:41 am
  • Editorial Team
    Editorial Team added an answer Someone could inject SQL to cause an authorization check to… May 12, 2026 at 8:41 am

Related Questions

I have a login form which appears at the top of all of my
Edit: I put this snippet of code in jsbin: http://jsbin.com/eneru I am trying to
I am using the following jQuery code to fill my DIV in the ASPX
I am using jquery to locate all the checkboxes in a table column that

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.