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Home/ Questions/Q 6780025
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:27:26+00:00 2026-05-26T16:27:26+00:00

I am using the following script to clone a div with form elements inside;

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I am using the following script to clone a div with form elements inside; however, it currently adding sequential numbers (1, 2, 3) to the container div id correctly, but then is adding a “name2” and “name3” to the sub-divs in the clone, instead of to the actual form elements.

Example of problem:

<div class="clonedInput" id="container1">
    <div>First Name:
        <input type="text" id="first_name1" name="first_name1">
    </div>
    <div>Last Name:
        <input type="text" id="last_name1" name="last_name1">
    </div>
    <div>Phone:
        <input type="text" id="phone1" name="phone1">
    </div>
</div>

<div class="clonedInput" id="container2">
    <div id="name2" name="name2">First Name:
        <input type="text" id="first_name1" name="first_name1">
    </div>
    <div>Last Name:
        <input type="text" id="last_name1" name="last_name1">
    </div>
    <div>Phone:
        <input type="text" id="phone1" name="phone1">
    </div>
</div>

<div class="clonedInput" id="container3">
    <div id="name3" name="name3">First Name:
        <input type="text" id="first_name1" name="first_name1">
    </div>
    <div>Last Name:
        <input type="text" id="last_name1" name="last_name1">
    </div>
    <div>Phone:
        <input type="text" id="phone1" name="phone1">
    </div>
</div>

Full code:

<html>
<head>
<title></title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
<script type="text/javascript">
jQuery( function ( $ ) {
    $( '#btnAdd' ).click( function() {
        var num = $( '.clonedInput' ).length;      // how many "duplicatable" input fields we currently have
        var newNum  = new Number( num + 1 );        // the numeric ID of the new input field being added
        var newElem = $( '#container' + num ).clone().attr( 'id', 'container' + newNum );

        newElem.children( ':first' ).attr( 'id', 'name' + newNum ).attr( 'name', 'name' + newNum );
        $( '#container' + num ).after( newElem );
        $( '#btnDel' ).attr( 'disabled', false );
        if ( newNum == 25 )
            $( '#btnAdd' ).attr( 'disabled', 'disabled' );
    });

    $( '#btnDel' ).click( function() {
        var num = $( '.clonedInput' ).length;      // how many "duplicatable" input fields we currently have
        $( '#container' + num ).remove();              // remove the last element
        $( '#btnAdd' ).attr( 'disabled', false );  // enable the "add" button

        // if only one element remains, disable the "remove" button
        if ( num-1 == 1 )
            $( '#btnDel' ).attr( 'disabled', 'disabled' );
    });

    $( '#btnDel' ).attr( 'disabled', 'disabled' );
});
        </script>
</head>

<body>
<form id="myForm">
    <div id="container1" class="clonedInput"> 
        <div>
        First Name:
        <input type="text" name="first_name1" id="first_name1">
        </div>
        <div>
        Last Name:
        <input type="text" name="last_name1" id="last_name1">
        </div>
        <div>
        Phone:
        <input type="text" name="phone1" id="phone1">
        </div>
    </div>
    <div>
        <input type="button" id="btnAdd" value="add another name" />
        <input type="button" id="btnDel" value="remove name" />
    </div>
</form>
</body>
</html>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:27:26+00:00Added an answer on May 26, 2026 at 4:27 pm

    The problem is this line here:

    newElem.children( ':first' ).attr( 'id', 'name' + newNum ).attr( 'name', 'name' + newNum );
    

    Only the first child of each newElem is being selected, which is why only the first input element is being changed. What you want to do is select ALL the children that are input elements. Try this:

    newElement.children('input').attr('id',$(this).attr('id') + newNum).attr('name',$(this).attr('name') + newNum);
    
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