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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T15:10:23+00:00 2026-05-13T15:10:23+00:00

I am using the following spinlock approach: while(!hasPerformedAction()){ //wait for the user to perform

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I am using the following spinlock approach:

while(!hasPerformedAction()){
    //wait for the user to perform the action
    //can add timer here too
}

setHasPerformedAction(false);

return getActionPerfomed();

this basically waits for a user to perform an action and then returns it. Currently something requests an answer from the user before continuing, this is why I wait until input is received. However I was wondering if this is inefficient and if we are waiting for a while (i.e. <= 30 secs) will it slow down the pc that is running this app. Are there any other alternatives using this approach i.e. locks, semaphores if so what is the syntax?

Thanks,

Aly

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  1. Editorial Team
    Editorial Team
    2026-05-13T15:10:24+00:00Added an answer on May 13, 2026 at 3:10 pm

    In fact, not only is this inefficient, it is not even guaranteed to work, since there is no “happens-before” edge in the code that you are showing. To create a happens-before edge you need to do one of:

    1. Access a volatile variable
    2. Synchronise on a shared resource
    3. Use a concurrent utils lock.

    As mentioned in another comment, the easiest solution, is simply to ensure that your flag is a volatile variable, and simply throw a short sleep in your loop.

    However, the best thing to do would be to synchronize/wait/notify on a shared variable.

    The methods that you need to read up on are wait and notify. For a better description on how to use these, read this article. An example code snippet is shown below;

    Thread 1

    Object shared = new Object();
    startThread2(shared);
    synchronized (shared) {
      while (taskNotDone())
        shared.wait();
    }
    

    Thread 2

    // shared was saved at the start of the thread
    // do some stuff
    markTaskAsDone();
    synchronized (shared) {
      shared.notify();
    }
    
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