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Home/ Questions/Q 5938379
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:40:38+00:00 2026-05-22T15:40:38+00:00

I am using the jquery .load() method for a search. I have figured out

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I am using the jquery .load() method for a search. I have figured out how to send one variable, but I need to send many.

WITH ONE

var field1 = ($('#form1 input[name="field1"]:text').val());
$('#results').load("/search/show.php", {field1: field1});

How would I do two variables? THIS WONT WORK

var field1 = ($('#form1 input[name="field1"]:text').val());
var field2 = ($('#form1 input[name="field2"]:text').val());
$('#results').load("/search/show.php", {field1: field1}{field2: field2});

I’m sure there is an easy way to send multiple variables, I just don’t know how!

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:40:39+00:00Added an answer on May 22, 2026 at 3:40 pm

    You’re looking for:

    var field1 = ($('#form1 input[name="field1"]:text').val());
    var field2 = ($('#form1 input[name="field2"]:text').val());
    $('#results').load("/search/show.php", {field1: field1, field2: field2});
    

    Check out object literals on the MDC.

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