Question

I am using the mysqli db class found at github

my query looks like

$db->query('
  SELECT
    memberID,zoneCode,state,zone,countyName,
    CONCAT(state,\'Z\',zone) as fullZoneCode
  FROM members_zonesToWatch
  LEFT JOIN (
    SELECT state,zone,countyName
    FROM countyPublicForcastZoneCorrelation
  ) as zones
    ON zoneCode = CONCAT(state,\'Z\',zone)');

The issue im getting is

Fatal error: Problem preparing query 
(SELECT
  memberID,zoneCode,state,zone,countyName,
   CONCAT(state,'Z',zone) as fullZoneCode
 FROM members_zonesToWatch
 LEFT JOIN (
   SELECT state,zone,countyName
   FROM countyPublicForcastZoneCorrelation
 ) as zones
   ON zoneCode = CONCAT(state,'Z',zone)) 
You have an error in your SQL syntax; check the manual that corresponds to your
MySQL server version for the right syntax to use near
''Z',zone) as fullZoneCode FROM members_zonesToWatch LEFT' at line 1

This query as it is works in mysql workbench just fine. What is wrong with it using the mysqli class?

Answer 1

After testing on your case, the problem is the 'Z' and $db->query

It is because the MysqliDB internally uses mysqli and mysqli throws the exception when prepare your statement (from the debugger, it seems the quote ' turns to ').

Instead, MysqliDB provide rawQuery for cases like yours. So use the below :

$result = $db->rawQuery('
    SELECT m.memberID, CONCAT(m.state, ? ,m.zone) as fullZoneCode
    FROM members_zonesToWatch m
    LEFT JOIN countyPublicForcastZoneCorrelation c
    ON c.zoneCode = CONCAT(m.state, ? ,m.zone)',
    array('Z','Z'));

Reference: PHP-MySQLi-Database-Class / MysqliDb.php;