Question

I am using the QuickDialog library, which is awesome!
I managed so far to place a json file into my project and display it.
But know I want to read it from a webservice. But the function takes a string. You can see the function over here.

- (QRootElement *)initWithJSONFile:(NSString *)jsonPath {
    self = [self initWithJSONFile:jsonPath andData:nil];
    return self;
}

What I do is the following.

[sectionSamples addElement:[[QRootElement alloc] initWithJSONFile:@"loginform"]];
[sectionSamples addElement:[[QRootElement alloc] initWithJSONFile:[NSURL URLWithString:[NSString stringWithFormat:@"%@",@"http://192.168.0.102/testWeb/callback2.json"]]]];

Like you can see my first element just loads a json (loginform) in that is located somewhere in my project. But when I want the second form (callback2.json) to load in. It says dataparameter is nil .

When I browse to the url in my browser it is correctly displaying it.

Can anybody help me?

Kind regards.

Answer 1

Ok, so the solution was to maken an override of the function initWithJsonFile, which takes an NSURL as parameter.

- (QRootElement *)initWithJSONURL:(NSURL *)jsonPath andData:(id)data{

    Class JSONSerialization = [QRootElement JSONParserClass];
    NSAssert(JSONSerialization != NULL, @"No JSON serializer available!");

    NSError *jsonParsingError = nil;
    //NSString *filePath = [[NSBundle mainBundle] pathForResource:jsonPath ofType:@"json"];
    NSDictionary *jsonRoot = [JSONSerialization JSONObjectWithData:[NSData dataWithContentsOfURL:jsonPath] options:0 error:&jsonParsingError];

    self = [self initWithJSON:jsonRoot andData:data];
    return self;
}