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Home/ Questions/Q 6595721
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:58:36+00:00 2026-05-25T17:58:36+00:00

I am using the rapidxml lib. It defines a function to parse files in

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I am using the rapidxml lib.
It defines a function to parse files in this way:

template<int Flags>
void parse(Ch *text)

The lib provides const int flags for example:

const int parse_declaration_node = 0x20;

So I created a pointer to a static int in my class:

const int * parser_mode;

And in the class constructor I assigned it its value:

parser_mode = &rapidxml::parse_declaration_node;

Then when I try to use this const int * as template argument to the parse function:

tree->parse<parser_mode>(file->data());

I get this error message:

error: ‘GpxSectionData::parser_mode’ cannot appear in a
constant-expression

This rest of the statement seems correct since:

tree->parse<0>(file->data());

doesn’t produce compilation error…

Could you please tell me what I am missing here?
Thank you!


Thanks to the explanations below I will probably define it out of the class:
So I think this is:

class Myclass {
static const int parser_mode;
[...]
}
static const int Myclass::parser_mode = rapidxml::parse_declaration_node;
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  1. Editorial Team
    Editorial Team
    2026-05-25T17:58:37+00:00Added an answer on May 25, 2026 at 5:58 pm

    template<int Flags> void parse(Ch *text) … const int * parser_mode;

    Your template takes an int as a template parameter, but you are passing it an int*. The types int and int* are not the same.

    Try tree->parse<rapidxml::parse_declaration_node>(file->data());

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