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Home/ Questions/Q 9136477
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T08:57:28+00:00 2026-06-17T08:57:28+00:00

I am using the underbelow link reference to publish share the link and title

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I am using the underbelow link reference to publish share the link and title on twitter but when I am clicking on the link only

http://twitter.com/home?status=test+http://www.test.com/cgi-bin/show_post.pl?view_mode=single&post_id=134 

but the tweet being generated, by the above link have url till

http://www.test.com/cgi-bin/show_post.pl?view_mode=single
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  1. Editorial Team
    Editorial Team
    2026-06-17T08:57:29+00:00Added an answer on June 17, 2026 at 8:57 am
    https://twitter.com/intent/tweet?source=webclient&text=test+http%3A%2F%2Fwww.test.com%2Fcgi-bin%2Fabc.pl%3Fa%3D1%26b%3D2
    

    All the special character in the shared link, need to be converted into hexa character

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