Question

I am using this code in JSLint

var string = "Hello";
if (string == "Hello") {
    string = "World";
}

And I am getting this error

Expected '===' and instead saw '=='.
if (string == "Hello") {

Why JSLint is throwing this error?

Answer 1

From JSLint docs under == and !=

The == and != operators do type coercion before comparing. This is bad
because it causes ‘ \t\r\n’ == 0 to be true. This can mask type
errors. JSLint cannot reliably determine if == is being used
correctly, so it is best to not use == and != at all and to always use
the more reliable === and !== operators instead.

If you only care that a value is truthy or falsy, then use the short
form. Instead of

(foo != 0)

just say

(foo)

and instead of

(foo == 0)

say

(!foo)

There is an eqeq option that allows the use of == and !=.

How to tell JSLint not to throw this error.

Use JSLint directive eqeq

like this

/*jslint eqeq: true*/

So the full code will look like

/*jslint eqeq: true*/
var string = "Hello";
if (string == "Hello") {
    string = "World";
}