Question

I am using this code to adapt my storyboard depending on device (iphone 5 or less):

if([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone){
    if(UIScreenOverscanCompensationScale==1136/640){
        //move to your iphone5 storyboard
        UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"iphone5 storyboard" bundle:[NSBundle mainBundle]];
    }
    else{
        //move to your iphone4s storyboard
        UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone" bundle:[NSBundle mainBundle]];
    }}

The code doesn’t work even if I just place:

UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"iphone5 storyboard" bundle:[NSBundle mainBundle]];

…it still loads iphone normal.

I put it under:

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{

in app delegate. Is this right?? In the app settings I chose the original iphone storyboard

Answer 1

I managed to solve it in this way:

if([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone){
    if([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && [UIScreen mainScreen].bounds.size.height == 568.0){
        //move to your iphone5 storyboard
        UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"iphone5 storyboard" bundle:[NSBundle mainBundle]];
        UIViewController *vc =[storyboard instantiateInitialViewController];

        // Set root view controller and make windows visible
        self.window.rootViewController = vc;
        [self.window makeKeyAndVisible];
    }
    else{
        //move to your iphone4s storyboard
        UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone" bundle:[NSBundle mainBundle]];
        UIViewController *vc =[storyboard instantiateInitialViewController];

        // Set root view controller and make windows visible
        self.window.rootViewController = vc;
        [self.window makeKeyAndVisible];
    }}