Question

I am using this code to display image from URL, but it is not working,

<?php
     echo 'me'.'<br/>';


      $sql= 'SELECT url_imgsrch FROM p_url_imgsrch';
      $result   =   mysql_query($sql);
        echo $result;
       $row = mysql_fetch_row($result);


      for ($i=0; $i<6; $i++){

        //calling rows
        echo '<td>';

//calling rows value for debugging purpose so that i can learn the process and check the output

         echo $row[$i].'<br/>';

echo '<img name="myimage" src="<?php echo $row[$i]; ?>" width="60" height="60" alt="word" />';

            echo '</td>';
            }

     ?>

The result is, I get alt text only, and image is not displayed. also, I get error

Notice: Undefined offset: 1 in D:\wamp\www\demo\login\flashcard.php on
line 31

In my file
What I am trying is, to get 5 img url from database and display them in columns of a table..and what I guess is I am getting same img URL again and again…for 5 times..

Please give me guideline and tell me what I could be missing…

Answer 1

i have never seen someone loop through a query that way, i do it like this:

print "<table>";
$sql= 'SELECT url_imgsrch FROM p_url_imgsrch LIMIT 5';
$result   =   mysql_query($sql);
 while($row = mysql_fetch_array($result)){
    print '<tr>
            <td>
               <img name="myimage" src="'.$row[column_name_here].'" width="60" height="60" alt="word" />
            </td>
          </tr>';
    }
print "</table>";

change column_name_here to the name of the column which store the image file name

edit: changed mysql_fetch_row to mysql_fetch_array <- that is why u got the same image all 5 times.