Question

I am using this code to export selected data from MySQL to CSV using PHP, I am facing a little problem that when data exported to the csv file it looks like below:

First line in its correct place, but starting from the second row data shifts to the right one space, if I open the csv file in Excel, I can see the most left cell after the first row is empty.

parts   destination 
===================     
1   9.71504E+11 
1   9.71504E+11
1   96656587662
1   9.71504E+11

This is my code :

$values =mysql_query( "SELECT parts,destination from log");

$rown = 0;
$row = array();
$row[] = 'parts';
$row[] = 'destination'."\n";
$data .= join(',', $row)."\n";

while( $row_select = mysql_fetch_assoc($values) ) {
  if($rown++==0)
    $row = array();

  $row[] = $row_select['parts'];
  $row[] = $row_select['destination']."\n";
}
$data .= join(',', $row)."\n";

$filename = $file."_".date("Y-m-d_H-i",time());
header("Content-type: text/csv");
header("Content-disposition: csv" . date("Y-m-d") . ".csv");
header( "Content-disposition: filename=".$filename.".csv");
print $data;
exit();

Would you please help?

Regards,

Answer 1

The problem is in the following line

$data .= join(',', $row)."\n";

You’re concatenating all the elements in $row with commas. So the destination of one row is concatenated with the parts of the next row with a comma in between, so you get something like this:

$data = $row_select['parts'] . ',' . $row_select['destination']."\n" . ',' . $row_select['parts'] etc...

The comma after the newline creates an empty cell at the beginning of the row.

UPDATE It should work with the following

while( $row_select = mysql_fetch_assoc($values)){
$row = array();
$row[] = $row_select['parts'];
$row[] = $row_select['destination']."\n";
$data .= join(',', $row);
}