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Home/ Questions/Q 599273
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:28:49+00:00 2026-05-13T16:28:49+00:00

I am using this code using isset to check if empty: if(!isset($this->objCodes[0]->SignupCode))$this->objCodes[0]->NULL; But it

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I am using this code using isset to check if empty:

    if(!isset($this->objCodes[0]->SignupCode))$this->objCodes[0]->"NULL";

But it doesn’t work. Help?

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:28:49+00:00Added an answer on May 13, 2026 at 4:28 pm

    You might want to use empty to check if the value has a value that might be useless. If your SignupCode will never be an empty string (""), 0, or another empty value, try this:

    if(empty($this->objCodes[0]->SignupCode))
    {
        $this->objCodex[0] = null;
    }
    

    The reason I normally use empty() is because if I am importing from a database, the data I am looking for will always return true to isset() because it was set by the database. I’m more interested if it is null or an empty string, as that means there really isn’t anything of value in the variable.

    If you are loading values into your object like this:

    $result = mysql_query("Some Query");
    while($temp = mysql_fetch_assoc($result)
    {
        $myObj = new stdClass;
        $myObj->SignupCode = $temp['SignupCode'];
        $myObjs[] = $myObj;
    }
    

    You will always recieve a true to the isset() function when testing like this:

    if(isset($myObjs[0]->SignupCode))
    

    Because the value is technically always going to be ‘set’

    If you are actually trying to see if it isn’t set at all, try this:

    if(!isset($this->objCodes[0]->SignupCode))
    {
        $this->objCodex[0] = null;
    }
    
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