Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6252669
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T13:50:46+00:00 2026-05-24T13:50:46+00:00

I am using this JPA-Query (EclipseLink): SELECT e FROM Entity e GROUP BY e.label

  • 0

I am using this JPA-Query (EclipseLink):

SELECT e FROM Entity e GROUP BY e.label

But i get all rows in my result instead of only the unique labels.

My second approach was using DISTINCT like i did successfully in another function which counts the distinct values, but i don’t know how apply this to get the Entities:

SELECT COUNT(DISTINCT e.label) FROM Entity e
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-24T13:50:47+00:00Added an answer on May 24, 2026 at 1:50 pm

    From the Hibernate JP-QL documentation:

    select distinct e.label from Entity e
    

    However, it seems you want the full entities, which I don’t think is possible.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am using This JPA-Query: SELECT DISTINCT e.label FROM Entity e GROUP BY e.label
I have entity model like this (using EclipseLink and JPA 2.0): @Entity class A
I'm using this script to display all the images in a folder, but I
I'm using JPA 2.0, more precisely Eclipselink. Here's my problem: I have an entity
I have a problem getting this JPA query to work on MS SQL Server
I'm using Hibernate/JPA and have an @Entity object called Order, pointing at a MySQL
I'm using EclipseLink as the JPA provider. Further I'm using the following TABLE_PER_CLASS inheritance
I need to change the value of a column using JPA query syntax(JPQL), how
I am writing a JPA QL named query that would search for documents. This
Using this question as the base is there an alogrithm or coding example to

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.