Question

I am using this pattern to remove all HTML tags (Java code):

String html="text <a href=#>link</a> <b>b</b> pic<img src=#>";
html=html.replaceAll("\\<.*?\\>", "");

System.out.println(html);

Now, I want to keep tag <a ...> (with </a>) and tag <img ...>

I want the result to be:

text <a href=#>link</a> b pic<img src=#>

How to do this?

---

I don’t need HTML parser to do this,

because I need this regex pattern to filter a lot of html fragment,

so,I want the solution with regex

Answer 1

You could do this using a negative lookahead:

"<(?!(?:a|/a|img)\\b).*?>"

Rubular

However this has a number of problems and I would recommend instead that you use an HTML parser if you want a robust solution.

For more information see this question:

• What HTML parsing libraries do you recommend in Java