Question

I am using this script to insert three different span‘s to the 1st, 2nd and 3rd lis.

$("ul li:eq(0)").prepend("<span>1</span>");
$("ul li:eq(1)").prepend("<span>2</span>");
$("ul li:eq(2)").prepend("<span>3</span>");

Is there a way to refactor this code to remove the redundancy?

Answer 1

If you want to do it to all li tags that are there:

$("ul li").each(function(i) {
    $(this).prepend("<span>" + (i + 1) + "</span>");
});

If there are more than three li tags and you only want it done to the first three:

$("ul li:lt(3)").each(function(i) {
    $(this).prepend("<span>" + (i + 1) + "</span>");
});

Working jsFiddle here: http://jsfiddle.net/jfriend00/qhgad/