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Home/ Questions/Q 7528325
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T04:20:52+00:00 2026-05-30T04:20:52+00:00

I am using this script to randomly load a style sheet on load. But

  • 0

I am using this script to randomly load a style sheet on load.
But I would also like to have a button on the site that can run the script so the user can load a new style by clicking on a button instead of F5.

Any suggestions on how to write this?
Cheers!

var link = [];
link[0] = "css/style1.css";
link[1] = "css/style2.css";
link[2] = "css/style3.css";

$(function() {
var style = link[Math.floor(Math.random() * link.length )];
$('<link />',{
                rel :'stylesheet',
                type:'text/css',
                href: style
             }).appendTo('head');
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T04:20:53+00:00Added an answer on May 30, 2026 at 4:20 am

    Just put your code in that button:

    HTML:

    <input type="button" id="btnID" />
    

    JS:

    $('#btnID').click(function(){
      var style = link[Math.floor(Math.random() * link.length )];
      $('<link />',{
                    rel :'stylesheet',
                    type:'text/css',
                    href: style
                 }).appendTo('head');
    });
    

    Assuming you have defined necessary variables on top of your script:

    var link = [];
    link[0] = "css/style1.css";
    link[1] = "css/style2.css";
    link[2] = "css/style3.css";
    
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