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Home/ Questions/Q 7897001
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T08:02:30+00:00 2026-06-03T08:02:30+00:00

I am using tomcat connection pool, jpa, hibernate. The datasource i created in context.xml

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I am using tomcat connection pool, jpa, hibernate. The datasource i created in context.xml of tomcat works fine if I try to get it using :

source = (DataSource) ((Context) c.lookup("java:comp/env")).lookup("jdbc/kids");

but if i specify this jndi datasource in persistence.xml

<persistence-unit name="kids-tomcat" transaction-type="JTA">
           <jta-data-source>jdbc/kids</jta-data-source>
       </persistence-unit>

I am getting following exception:
org.hibernate.service.jndi.JndiException: Unable to lookup JNDI name [jdbc/kids]

Any idea why it could happen !

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  1. Editorial Team
    Editorial Team
    2026-06-03T08:02:32+00:00Added an answer on June 3, 2026 at 8:02 am

    Finally it worked today after i specified the properties below.. because just mentioning the datasource is not enough; we need to specify some properties like which dialect to use. If we specify datasource; we need not specify username , password url of the database ( as all are specified in the datasource configuration itself) .

    Most important point is the way you specify the datasource. It should be complete path: java:/comp/env/jdbc/kids . All this while I was missing the slash just before comp.

    <persistence-unit name="kids" transaction-type="RESOURCE_LOCAL">
        <non-jta-data-source>java:/comp/env/jdbc/kids</non-jta-data-source>
        <class>com.kids.domain.User</class>
        <properties>
            <property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect"/>
            <property name="connection.autocommit" value="false"/>
            <property name="hibernate.hbm2ddl.auto" value="create"/>
            <property name="hibernate.show_sql" value="true"/>
        </properties>
    </persistence-unit>
    

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