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Home/ Questions/Q 8453519
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Editorial Team
  • 0
Editorial Team
Asked: June 10, 20262026-06-10T11:47:45+00:00 2026-06-10T11:47:45+00:00

I am using two actions one for the get portion of my request (a

  • 0

I am using two actions one for the get portion of my request (a generic looking url) and another for the post.

In the case that a post has ModelState errors, I would like to view to return to show the errors but I would like the url to be the generic url.

So this is what currently happens:

Get: http://foo.com/mycontroller  
Post: http://foo.com/mycontroller/specificviewaction (validation error occurs)  
Resultant url is: http://foo.com/mycontroller/specificviewaction

Where as I want it to be http://foo.com/mycontroller the appropriate errors.

Here is my current code:

    public ActionResult Index()
    {
        // ... do stuff
        return View("specificviewaction ", model);
    }

    [HttpPost] 
    public ActionResult specificviewaction(Model model)
    {
        if (ModelState.IsValid)
        {
        // ... do stuff
        }

        return View("specificviewaction", model);
    }

Note, there is no actual Index view, only specific views.

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  1. Editorial Team
    Editorial Team
    2026-06-10T11:47:47+00:00Added an answer on June 10, 2026 at 11:47 am

    This is what I ended up doing.

    I left the routing table as per the default implementation.

    Then for each model type, I am putting a hidden field in the form with which type it is.

    On the post, I check what type it is and use TryUpdateModel to update an instance of the model with the correct form values.

    If it succeeds great, if not I can deliver the appropriate errors back.

    I was trying to over think it, simplest approach was best.

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