Question

I am using Windows Form and MySQL for my project. In that i want to save a image and retrieve that.

I have created a table named ‘image’ in that,

CREATE TABLE `image` (
    `id` INT(15) NOT NULL AUTO_INCREMENT,
    `extension` VARCHAR(50) NOT NULL,
    `image` LONGBLOB NOT NULL,
    PRIMARY KEY (`id`)
)
ENGINE=MyISAM
ROW_FORMAT=DEFAULT
AUTO_INCREMENT=2

And

OpenFileDialog open = new OpenFileDialog();
            // image filters
            open.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp; *.png)|*.jpg; *.jpeg; *.gif; *.bmp; *.png";
            if (open.ShowDialog() == DialogResult.OK)
            {                
                txt_imagePath.Text = open.FileName;
            }

            hp.getConnStr();
            try
            {
                MySqlConnection connection = new MySqlConnection(hp.myConnStr);
                MySqlCommand command = connection.CreateCommand();                
                command.CommandText = "insert into image (image) values ('"+txt_imagePath.Text +"')";
                command.Connection.Open();
                command.ExecuteNonQuery();
                command.Connection.Close();
            }

in Browse button click event,..

The file is successfully saved. Now i want to retrieve that picture and show in picture box. So that i try this bellow code,..

 MySqlConnection connection = new MySqlConnection(hp.myConnStr);
                MySqlCommand command = connection.CreateCommand();
                MySqlDataReader Reader;
                command.CommandText = "select image from image";
                connection.Open();
                Reader = command.ExecuteReader();
                while (Reader.Read())
                {
                   pictureBox1.Image = new Bitmap(Reader[0].ToString()); 
                }
                connection.Close(); 

but no use.

Please help me.

Answer 1

You should read the blob field as a MemoryStream and set to Image property of the control using Image.FromStream().