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Home/ Questions/Q 790345
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T21:40:03+00:00 2026-05-14T21:40:03+00:00

I am using windows, Mysql DB, PHP I am building the Joomla Component whose

  • 0

I am using windows, Mysql DB, PHP

I am building the Joomla Component whose one of the functionality is to synchronize the folders
I want to sync two folders of different name.. How can I do this? It has to be dne in the same machine, no two different servers are involved in it..

How to sync two folders in PHP?

UPDATED

IN Context of Alex Reply

What if i am editing any .jpg file in one folder and saving it with same name as it has, also this file is already present in other folder. And I want this edited pic to be transfered to the other folder.? also I have Joomla’s nested file structured to be compared

UPDATE 2

I have a recursive function which will output me the complete structure of folder… if u can just use it to concat ur solution in…

<?
function getDirectory($path = '.', $ignore = '') {
    $dirTree = array ();
    $dirTreeTemp = array ();
    $ignore[] = '.';
    $ignore[] = '..';

    $dh = @opendir($path);

    while (false !== ($file = readdir($dh))) {

        if (!in_array($file, $ignore)) {
            if (!is_dir("$path/$file")) {
                $stat = stat("$path/$file");
                $statdir = stat("$path");
                $dirTree["$path"][] = $file. " === ". date('Y-m-d H:i:s', $stat['mtime']) . " Directory == ".$path."===". date('Y-m-d H:i:s', $statdir['mtime']) ;

            } else {

                $dirTreeTemp = getDirectory("$path/$file", $ignore);
                if (is_array($dirTreeTemp))$dirTree = array_merge($dirTree, $dirTreeTemp);
            }
        }
    }
    closedir($dh);

    return $dirTree;
}


$ignore = array('.htaccess', 'error_log', 'cgi-bin', 'php.ini', '.ftpquota');

$dirTree = getDirectory('.', $ignore);
?>
<pre>
    <?
    print_r($dirTree);
    ?>
</pre> 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T21:40:03+00:00Added an answer on May 14, 2026 at 9:40 pm

    I just ran this, and it seems to work

    function sync() {
    
        $files = array();
        $folders = func_get_args();
    
        if (empty($folders)) {
            return FALSE;
        }
    
        // Get all files
        foreach($folders as $key => $folder) {
            // Normalise folder strings to remove trailing slash
            $folders[$key] = rtrim($folder, DIRECTORY_SEPARATOR);   
            $files += glob($folder . DIRECTORY_SEPARATOR . '*');    
        }
    
        // Drop same files
        $uniqueFiles = array();
        foreach($files as $file) {
            $hash = md5_file($file);
    
            if ( ! in_array($hash, $uniqueFiles)) {
                $uniqueFiles[$file] = $hash; 
            }
        }
    
    
        // Copy all these unique files into every folder
        foreach($folders as $folder) {
            foreach($uniqueFiles as $file => $hash) {
                    copy($file, $folder . DIRECTORY_SEPARATOR . basename($file));
            }
        }
        return TRUE;    
    }
    
    // usage
    
    sync('sync', 'sync2');
    

    You simply give it a list of folders to sync, and it will sync all files. It will attempt to skip files that appear the same (i.e. of whom their hash collides).

    This however does not take into account last modified dates or anything. You will have to modify itself to do that. It should be pretty simple, look into filemtime().

    Also, sorry if the code sucks. I had a go at making it recursive, but I failed 🙁

    For a one way copy, try this

    $source = '/path/to/source/';
    $destination = 'path/to/destination/';
    
    $sourceFiles = glob($source . '*');
    
    foreach($sourceFiles as $file) {
    
        $baseFile = basename($file);
    
        if (file_exists($destination . $baseFile)) {
    
            $originalHash = md5_file($file);
            $destinationHash = md5_file($destination . $baseFile);
            if ($originalHash === $destinationHash) {
                continue;
            }
    
        }
        copy($file, $destination . $baseFile);
    }
    

    It sounds like you just want to copy all files from one folder to another. The second example will do this.

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