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Home/ Questions/Q 8024345
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T22:50:42+00:00 2026-06-04T22:50:42+00:00

I am using XMLHttpRequest to send a file from javascript code to a django

  • 0

I am using XMLHttpRequest to send a file from javascript code to a django view.I need to detect,whether the file has been sent or if some error occurred.I used jquery to write the following javascript.

Ideally I would like to show the user an error message that the file was not uploaded.Is there some way to do this in javascript?

I tried to do this by returning a success/failure message from django view , putting the success/failed message as json and sending back the serialized json from the django view.For this,I made the xhr.open() non-asynchronous. I tried to print the xmlhttpRequest object’s responseText .The console.log(xhr.responseText) shows

response= {"message": "success"}

What I am wondering is,whether this is the proper way to do this.In many articles,I found the warning that

Using async=false is not recommended

So,is there any way to find out whether the file has been sent,while keeping xhr.open() asynchronous?

$(document).ready(function(){
   $(document).on('change', '#fselect', function(e){
            e.preventDefault();
            sendFile();
        });
});

function sendFile(){
   var form = $('#fileform').get(0);
   var formData = new FormData(form);
   var file = $('#fselect').get(0).files[0];
   var xhr = new XMLHttpRequest();
   formData.append('myfile', file);
   xhr.open('POST', 'uploadfile/', false);
   xhr.send(formData);
   console.log('response=',xhr.responseText);
}

My django view extracts file from form data and writes to a destination folder.

def store_uploaded_file(request):
   message='failed'
   to_return = {}
   if  (request.method == 'POST'):          
      if request.FILES.has_key('myfile'):
         file = request.FILES['myfile']
         with open('/uploadpath/%s' % file.name, 'wb+') as dest:
            for chunk in file.chunks():
               dest.write(chunk)
               message="success"
   to_return['message']= message
   serialized = simplejson.dumps(to_return)
   if store_message == "success":
      return HttpResponse(serialized, mimetype="application/json")
   else:
      return HttpResponseServerError(serialized, mimetype="application/json")

EDIT:

I got this working with the help of @FabrícioMatté

xhr.onreadystatechange=function(){
       if (xhr.readyState==4 && xhr.status==200){
          console.log('xhr.readyState=',xhr.readyState);
          console.log('xhr.status=',xhr.status);
          console.log('response=',xhr.responseText);

          var data = $.parseJSON(xhr.responseText);
          var uploadResult = data['message']
          console.log('uploadResult=',uploadResult);

          if (uploadResult=='failure'){
             console.log('failed to upload file');
             displayError('failed to upload');
          }else if (uploadResult=='success'){
             console.log('successfully uploaded file');
          }
       }
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T22:50:43+00:00Added an answer on June 4, 2026 at 10:50 pm

    XMLHttpRequest objects contain the status and readyState properties, which you can test in the xhr.onreadystatechange event to check if your request was successful.

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