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Home/ Questions/Q 6978671
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T17:47:13+00:00 2026-05-27T17:47:13+00:00

i am using ZendFrameWork 1.11.5 i need to make a Multi form search queries

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i am using ZendFrameWork 1.11.5
i need to make a Multi form search queries like i have 5 fields like

name (text box)
city (dropDown)
zipCode (text box)
type (dropdown)

now the problem is …
in text Box user can enter anything it could be correct info or not..
kindly suggest me how to build a fast query.what kind of options i have..
also i tried this but not working.. not giving me correct result..

Select * from table where type =       '%$pType%'
                OR  sex     LIKE     '%$sex%'
                OR  race    LIKE      '%$race%'
                OR  kind    LIKE     '%$kind%'
                OR  country LIKE      '%$Country%'
                OR  state   LIKE     '%$statesIDs%'
                OR  zipcode LIKE     '%$zip%'";
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T17:47:13+00:00Added an answer on May 27, 2026 at 5:47 pm

    Here is my sample code for you. Your code should depends on your needs, query may joins with another table, or instead of LIKE you can use MATCH...AGAINST for more accuracy result. This code depends on each parameter that user enter for making a final query.

    //In DbTable
    public function search($params)
    {
        $query = $this->select()
                       ->from(
                        array('tbl'=>'table'),
                        array('name','city','zipcode','type')
                        );
        $query = $this->_makeParams($query,$params);
        return $this->fetchAll($query);
    }
    
    private function _makeParams($query, $params)
    {
        $name = isset($params['name']) ? trim($params['name']) : '';
        $city = isset($params['city']) ? trim($params['city']) : '';
        $zipcode = isset($params['zipcode']) ? trim($params['zipcode']) : '';
        $type = isset($params['type']) ? trim($params['type']) : '';
    
        if($name!='')
        {
            $name = '%'.$this->quote($name).'%';//quote is my own function
            $query->where("tbl.name LIKE '?'",$name); 
        }
    
        if($city!='')
        {
            $query->where("tbl.city=?",$city);
        }
    
        if($zipcode!='')
        {
            $query->where("tbl.zipcode=?",$zipcode);
        }
    
        if($type!='')
        {
            $query->where("tbl.type=?",$type);
        }
    
        return $query;
    
    }
    
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