Question

i am very new to regular expression and trying get “\” character using python

normally i can escape “\” like this

print ("\\");
print ("i am \\nit");

output

\
i am \nit

but when i use the same in regX it didn’t work as i thought

print (re.findall(r'\\',"i am \\nit"));

and return me output

['\\']

can someone please explain why

Answer 1

EDIT: The problem is actually how print works with lists & strings. It prints the representation of the string, not the string itself, the representation of a string containing just a backslash is '\\'. So findall is actually finding the single backslash correctly, but print isn’t printing it as you’d expect. Try:

>>> print(re.findall(r'\\',"i am \\nit")[0])
\

---

(The following is my original answer, it can be ignored (it’s entirely irrelevant), I’d misinterpreted the question initially. But it seems to have been upvoted a bit, so I’ll leave it here.)

The r prefix on a string means the string is in “raw” mode, that is, \ are not treated as special characters (it doesn’t have anything to do with “regex”).

However, r'\' doesn’t work, as you can’t end a raw string with a backslash, it’s stated in the docs:

Even in a raw string, string quotes can be escaped with a backslash, but the backslash remains in the string; for example, r”\”” is a valid string literal consisting of two characters: a backslash and a double quote; r”\” is not a valid string literal (even a raw string cannot end in an odd number of backslashes). Specifically, a raw string cannot end in a single backslash (since the backslash would escape the following quote character).

But you actually can use a non-raw string to get a single backslash: "\\".