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Home/ Questions/Q 189941
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T16:12:51+00:00 2026-05-11T16:12:51+00:00

I am very very new to xml. I am developing an application which uses

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I am very very new to xml. I am developing an application which uses xml file. I created this file with the help of Google. My sample xml file is:

<?xml version="1.0"?>
<gamelist>
 <game>
  <title>Driver</title>
  <code><EMBED src="http://www.pnflashgames.com/modules/pnFlashGames/games/racer.swf"></EMBED></code>
  <rating>4</rating>
 </game>
 <game>
  <title>ConeCrazy</title>
  <code><EMBED     src="http://www.pnflashgames.com/modules/pnFlashGames/games/ConeCrazy.swf"></EMBED></code>
  <rating>3</rating>
 </game>
</gamelist>

In the above file code element is having embed tag. For my application I need embed tag as a string. In code element if I use any string instead of embed tag I can read that string. If I use embed tag I am getting error like this:

[fatal error] gamelist.xml:5:103 : reference to entity “pn_uname” must end with the “;” delimeter .

I am using Java for reading xml file. In my Java class I want the whole embed tag as a string.

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  1. Editorial Team
    Editorial Team
    2026-05-11T16:12:51+00:00Added an answer on May 11, 2026 at 4:12 pm

    I suppose you are not generating the XML with suitable tools (a DOM API), but by concatenating strings.

    If further suppose the XML you are showing in your question is not the one that triggers the error.

    I think you have something like this:

    <EMBED src="http://foo/bar/racer.swf?bla&pn_uname=baz"></EMBED>
    

    This would trigger an error message stating that the character entity “pn_uname” is not well-formed.

    The correct way to express the above would be:

    <EMBED src="http://foo/bar/racer.swf?bla&amp;pn_uname=baz"></EMBED>
    

    …which is what using an API for XML generation would automatically handle for you. Avoid string concatenation to produce XML.

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