Question

I am wondering how to get the Json value ?(from below JSOn I would like to get product’s”Price” so that I can add into total. thank you very much.

{ "StatusCode": 0
, "StatusInfo": "Processed and Logged OK"
, "PageNumber": 0
, "TotalPageCount": 1
, "TotalProductCount": 1
, "PageProductCount": 1
, "Products": [
  { "BaseProductId": "54158094"
  , "EANBarcode": "3068320055008"
  , "CheaperAlternativeProductId": ""
  , "HealthierAlternativeProductId": ""
  , "ImagePath": "http://img.tesco.com/Groceries/pi/008/3068320055008/IDShot_90x90.jpg"
  , "MaximumPurchaseQuantity": 99
  , "Name": "UNAVAILABLE: Evian Natural Mineral Water 500 Ml"
  , "OfferPromotion": ""
  , "OfferValidity": ""
  , "OfferLabelImagePath": ""
  , "Price": 0.51
  , "PriceDescription": "(Unavailable)"
  , "ProductId": "258247301"
  , "ProductType": "QuantityOnlyProduct"
  , "UnitPrice": 0.004
  , "UnitType": "100ml" } ] }

Answer 1

Price tag value is not int its double so use double,,if you want int

then getInt from jsonobject but it return 0.due to 0.5 values…

         try {
                    String str="{ \"StatusCode\": 0....";
            JSONObject objJsonObject = new JSONObject(str);
            JSONArray array = objJsonObject.getJSONArray("Products");

               Double d =array.getJSONObject(0).getDouble("Price");
               System.out.print(d);
            }

        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }