Question

I am working in a bash shell and I am trying to print only the line of the first occurrence of the string. For example, for the string ‘auir‘, if I have the file myfile.txt and it contains:

123
asdf
4wirajw
forauir somethingelse
starcraft
mylifeforauir
auir
something else
tf.rzauir

I want to output “forauir somethingelse“

So far, I use the command

sed -n '/auir/p' myfile.txt

which gives me all the occurrences of this string. How can I only get the first line that ‘auir‘ occurs on? It’d be great if it was just a single command or pipeline of commands.

Any insight is greatly appreciated.

Answer 1

This sed command

sed -n '/auir/p' myfile.txt | head -1

solves your problem.