Question

I am working on a bash script to copy configuration files to their appropriate directories. I would like to output the name of the file that I have copied to the user. Here is what I have so far:

CONFIG_DIR="/home/stackoverflow/app/configs"
CONFIG_FILE="*.config"

cp $CONFIG_FILE $CONFIG_DIR

echo "$CONFIG_FILE was copied to $CONFIG_DIR"

The output I get from this is:

*.config was copied to /home/stackoverflow/app/configs

Let’s assume that stackoverflow.config is the only .config file present in the directory where the script is running. I would like it to say:

stackoverflow.config was copied to /home/stackoverflow/app/configs

Answer 1

Either add -v to copy and have it print all the file names (one name per line) or change the echo to

echo $CONFIG_FILE was copied to $CONFIG_DIR

i.e. remove the double quotes (they are not necessary in this example).