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Home/ Questions/Q 234369
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:10:46+00:00 2026-05-11T20:10:46+00:00

I am working on a circular problem. In this problem, we have objects that

  • 0

I am working on a circular problem. In this problem, we have objects that are put on a ring of size MAX, and are assigned IDs from (0 to MAX-1).

I have three simple functions to test for range inclusions. inRange(i,j,k) tests if i is in the circular interval [j,k[ (Mnemonic is i inRange(j,k)). And I have the same for ranges ]j,k[ and ]j,k].

Code in those three methods look duplicated from one method to another:

def inRange(i,j,k):
    """
    Returns True if i in [j, k[
    * 0 <= i, j, k < MAX
    * no order is assumed between j and k: we can have k < j
    """
    if j <= k:
        return j <= i < k
    # j > k :
    return j <= i or i < k

def inStrictRange(i,j,k):
    """
    Returns True if i in ]j, k[
    * 0 <= i, j, k < MAX
    * no order is assumed between j and k: we can have k < j
    """
    if j <= k:
        return j < i < k
    # j > k :
    return j < i or i < k

def inRange2(i,j,k):
    """
    Returns True if i in ]j, k]
    * 0 <= i, j, k < MAX
    * no order is assumed between j and k: we can have k < j
    """
    if j <= k:
        return j < i <= k
    # j > k :
    return j < i or i <= k

Do you know any cleaner way to implement those three methods? After all, only the operators are changing?!

After thinking of a better solution, I came up with:

from operator import lt, le
def _compare(i,j,k, op1, op2):
    if j <= k:
        return op1(j,i) and op2(i,k)
    return op1(j,i) or op2(i,k)

def inRange(i,j,k):
    return _compare(i,j,k, le, lt)
def inStrictRange(i,j,k):
    return _compare(i,j,k, lt, lt)
def inRange2(i,j,k):
    return _compare(i,j,k, lt, le)

Is it any better? Can you come up with something more intuitive?
In short, what would be the Pythonic way to write these three operators?

Also, I hate the inRange, inStrictRange, inRange2 names, but I can’t think of crystal-clear names. Any ideas?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:10:46+00:00Added an answer on May 11, 2026 at 8:10 pm

    Now I am thinking of something such as:

    def comparator(lop, rop):
        def comp(i, j, k):
            if j <= k:
                return lop(j, i) and rop(i,k)
            return lop(j, i) or rop(i,k)
    
        return comp
    
    from operator import le, lt
    
    inRange = comparator(le, lt)
    inStrictRange = comparator(lt, lt)
    inRange2 = comparator(lt, le)
    

    Which looks better indeed.

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