Question

I am working on a combination of coffeescript and require.js for AMD.

The problem would be that I must return a value for each module loaded by require.js, and I do that. But.. coffeescript helps me out and appends:(function() { and }).call(this);. which blows my code.

main.js

require.config( {
    paths: {
        'backbone':         'libs/AMDbackbone-0.5.3',
        'underscore':       'libs/underscore-1.2.2',
        'text':             'libs/require/text',
        'jquery':           'libs/jquery-1.7.1',
    },
    baseUrl: '/app'
} );

require(
        ['require', 'backbone', 'jquery', 'underscore' ],
        function( require, Backbone, $, _ ) {
            // framework loaded
            require(
                    ['require', 'app'],
                    function( require, app) {
                        return {};
                    } );
        } );

app.js

define( [
    'jquery',
    'underscore',
    'backbone',
    'views/gameview',
], function( $, _, Backbone, GameView, ) {
    "use strict";

    window.app = {};

    $(function(){

        var app = window.app = _.extend({

            views: {
                GameView: new GameView
            },
            //code..
        }, window.app);

    //code...
    return window.app;
} );

And the coffeescript:

/views/gameview.coffee

define ["jquery", "underscore", "backbone"], ($, _, Backbone, RankView) ->
  "use strict"
  GameView = Backbone.View.extend()
  GameView

Which translates to:

/views/gameview.js

(function() {

  define(["jquery", "underscore", "backbone"], function($, _, Backbone) {
    "use strict";

    var GameView;
    GameView = Backbone.View.extend({...});
    return GameView;
  });

}).call(this);

But I would like to translate to:

  define(["jquery", "underscore", "backbone"], function($, _, Backbone) {
    "use strict";

    var GameView;
    GameView = Backbone.View.extend({...});
    return GameView;
  });

Would be nice to use this in console: var GameView = new app.views.GameView; in console.

How do I force coffeescript compiler not to do that? Is there a flag or something for that?

AGAIN: I JUST WANT TO CUT OFF (function() { and }).call(this); – is not that important the amd code behind it, be it global or not..

Thank you

Answer 1

You can use the --bare flag when compiling your coffee files:

-b, --bare Compile the JavaScript without the top-level function safety wrapper.