Question

I am working on a function that sends emails with an attachment in PYTHON. In order to attach the file, I have to put it with the complete URL from the server, but the name of the file includes the hole URL. How can extrac only the filename from the URL.

I get the file from this URL:
/var/www/RH/HV/FILE.doc

And I want the attachment to appear
FILE.doc

here is the part of the code where i think the instructions should be added…

    #adjunto
    adjunto = MIMEBase('application', "octet-stream")
    adjunto.set_payload(open(file, "rb").read())
    encode_base64(adjunto)
    adjunto.add_header('Content-Disposition', 'attachment; filename= "%s"' % file)
    msg.attach(adjunto)

I hope someone could help!
THKS!!!

Answer 1

Use os.path.basename():

import os.path

p = '/var/www/RH/HV/FILE.doc'
print os.path.basename(p)

This assumes you’re working with normal file paths, not URLs. But based on the question it looks like you’re not looking at URLs.