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Home/ Questions/Q 5983113
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:11:02+00:00 2026-05-22T22:11:02+00:00

I am working on a generic utility method that takes a generic argument and

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I am working on a generic utility method that takes a generic argument and returns a generic type–I hope that makes sense!–but I want the return type to be a different type from the argument.

Here’s what I’m thinking this should look like if I mock it up in pseudo code:

public static IEnumerable<R> DoSomethingAwesome<T>(T thing) 
{
    var results = new List<R>();

    for (int xx = 0; xx < 5; xx++)
    {
        results.Add(thing.ToRType(xx));
    }

    return results;
}

With generics not being able to infer the return type how would I go about doing something like this? So far, my Google-Fu has failed me.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T22:11:03+00:00Added an answer on May 22, 2026 at 10:11 pm
    // You need this to constrain T in your method and call ToRType()
    public interface IConvertableToTReturn
    {
        object ToRType(int someInt);
    }
    
    public static IEnumerable<TReturn> DoSomethingAwesome<T, TReturn>(T thing)
        where T : IConvertableToTReturn
    {
        Enumerable.Range(0, 5).Select(xx => thing.ToRType(xx));
    }
    
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