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Home/ Questions/Q 5989565
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T23:07:11+00:00 2026-05-22T23:07:11+00:00

I am working on a mobile library app. I have a 3-4 db files

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I am working on a mobile library app. I have a 3-4 db files of books stored in raw folder. If I know the name of the book then I first copy this file to /databases/book_name.db and then access them as required. I use

InputStream fileInputStream = getResources().openRawResource(R.raw.book_name);

for accessing these files.

Now, I want to pass the book name and then dynamically generate the resource identifier R.raw.book_name using the string book_name. Is there a way by which I can generate this identifier?

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  1. Editorial Team
    Editorial Team
    2026-05-22T23:07:12+00:00Added an answer on May 22, 2026 at 11:07 pm

    Use Resources.getIdentifier() method:

    int resId = getResources().getIdentifier("raw/book_name", null, this.getPackageName());
    

    If your code not in activity or application, you need to get Context first.

    Context context = getContext(); // or getBaseContext(), or getApplicationContext()
    int resId = context.getResources().getIdentifier("raw/book_name", null, context.getPackageName());
    
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