Question

I am working on a report module that shows the time spent and number of tasks. The values are set in the Java Bean and the bean object is stored in a array.I am using separate queries to get time and number of tasks.Now i have to sort the array based on time and number of tasks.
The code below compares only Strings:

if (!list.isEmpty()) {
    Collections.sort(list, new Comparator<Project>() {
        @Override
        public int compare(Project p1, Project p2) {

            return p1.getName().compare(p2.getName());
        }
       });
   }

I have problems in sorting the integer value of a property in JavaBean which is stored in an array.Any help is greatly appreciated.

Answer 1

In your comments below the question you say you have:

Project[] array = new Project[3];

If I were you I’d declare Project as

public class Project implements Comparable<Project> {

    @Override
    public int compareTo(Project other) {
        return this.id - other.id; // or whatever property you want to sort
    }

Then you can sort your array by simply calling

Arrays.sort(array);

If you don’t want your class to implement the Comparable interface you can pass a comparator to Arrays.sort():

    Arrays.sort(array, new Comparator<Project>() {
        @Override
        public int compare(Project o1, Project o2) {
            return o1.id - o2.id; // or whatever property you want to sort
        }
    });

I used an anonymous one, you could also extract it to it’s own class if needed elsewhere.