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Home/ Questions/Q 97041
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Editorial Team
Asked: May 10, 20262026-05-10T23:55:43+00:00 2026-05-10T23:55:43+00:00

I am working on a UNIX box, and trying to run an application, which

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I am working on a UNIX box, and trying to run an application, which gives some debug logs to the standard output. I have redirected this output to a log file, but now wish to get the lines where the error is being shown.

My problem here is that a simple

cat output.log | grep FAIL 

does not help out. As this shows only the lines which have FAIL in them. I want some more information along with this. Like the 2-3 lines above this line with FAIL. Is there any way to do this via a simple shell command? I would like to have a single command line (can have pipes) to do the above.

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  1. 2026-05-10T23:55:44+00:00Added an answer on May 10, 2026 at 11:55 pm

    grep -A $NUM

    This will print $NUM lines of trailing context after matches.

    -B $NUM prints leading context.

    man grep is your best friend.

    So in your case:

    cat log | grep -A 3 -B 3 FAIL

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