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Home/ Questions/Q 7913347
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T13:49:18+00:00 2026-06-03T13:49:18+00:00

I am working on an application that used JDom for parsing XML documents. Following

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I am working on an application that used JDom for parsing XML documents.

Following is the existing code:

private Document openDocumentAtPath(File file) {

        // Create a sax builder for building the JDOM document
        SAXBuilder builder = new SAXBuilder();

        // JDOM document to be created from XML document
        Document doc = null;

        // Try to build the document
        try {

            // Get the file into a single string
            BufferedReader input =  new BufferedReader(
                new FileReader( file ) );
            String content = "";
            String line = null;
            while( ( line = input.readLine() ) != null ) {
                content += "\n" + line;
            }

            StringReader reader = new StringReader( content );
            doc = builder.build(reader);


        }// Only thrown when a XML document is not well-formed
        catch ( JDOMException e ) {
            System.out.println(this.file + " is not well-formed!");
            System.out.println("Error Message: " + e.getMessage());
        } 
        catch (IOException e) {
            System.out.println("Cannot access: " + this.file.toString());
            System.out.println("Error Message: " + e.getMessage());
        }
        return doc;
    }

Now I also want to validate the XML against an XSD. I read the API and it tells to use JAXP and stuff and I don’t know how.

The application is using JDom 1.1.1 and the examples I found online used some classes that are not available in this version. Can someone explain how to validate an XML against an XSD, especially for this version.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T13:49:20+00:00Added an answer on June 3, 2026 at 1:49 pm

    How about simply copy-pasting code from the JDOM FAQ?

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