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Home/ Questions/Q 7801587
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T00:59:46+00:00 2026-06-02T00:59:46+00:00

I am working on an embedded system (ARM Cortex M3) where I do not

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I am working on an embedded system (ARM Cortex M3) where I do not have access to any sort of “standard library”. In particular, I do not have access to malloc.

I have a function void doStuff(uint8_t *buffer) that accepts a pointer to a 512 bits buffer. I have tried doing the following:

uint8_t buffer[64] = {0};
doStuff((uint8_t *) &buffer));

but I’m not getting the expected results. Am I doing something wrong? Is there any alternative approach?

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  1. Editorial Team
    Editorial Team
    2026-06-02T00:59:48+00:00Added an answer on June 2, 2026 at 12:59 am

    doStuff(buffer) shall be ok since buffer is already an uint8_t*.

    Aside of this, you’re closing one bracket too much after &buffer in your example.


    If buffer is of variable size, you should pass the size into doStuff too, if it’s of constant size, I’d also pass the size just in case that you change the size one day.

    This being said, you should do it the following way:

    uint8_t buffer[64] = {0};
    int     len        = 64;
    doStuff(buffer, len);
    
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