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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T19:22:23+00:00 2026-05-31T19:22:23+00:00

I am working on android chat application. I am facing a problem in send

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I am working on android chat application. I am facing a problem in send and receive function using xmpp. I am able to send message from emulator to xmpp and receive message from xmpp. But i am facing issue in displaying the incoming and outgoing message in a list view. I am confused how to give the condition to set view layout.

if(message from xmpp) {
    TextView textLabel = (TextView) row.findViewById(R.id.textb); // if message received dislay in left side textview
    textLabel.setText(receiveddata); //receiveddata contains arraylist of incoming message
} else (message from me) {
    TextView textLabel = (TextView) row.findViewById(R.id.texts); // if message sent by me dislay in right side textview
    textLabel.setText(sentdata); //sentdata contains arraylist of outgoing message
}

Kindly tell me how can i do this.

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-31T19:22:24+00:00Added an answer on May 31, 2026 at 7:22 pm

    You can create an adapter class having two layout having same field. use if condition for incoming and outgoing messages. and inflate accordingly.

    public View getView(int position, View convertView, ViewGroup parent) {
            ViewHolder holder = null;
    
            entry = list.get(position);
    
            if (convertView == null) {
                if (getItemViewType(position) == 0) {
                    convertView = inflator.inflate(
                            R.layout.messages_even_list_layout, null);
                } else {
                    convertView = inflator.inflate(
                            R.layout.messages_odd_list_layout, null);
                }
    
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