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Home/ Questions/Q 9239357
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T07:58:09+00:00 2026-06-18T07:58:09+00:00

I am working on project using java playframework 1.2.4 and I have a @Entity

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I am working on project using java playframework 1.2.4 and I have a @Entity class. It is look like

@Entity
public class EmployeeType extends Model {
    public static enum TYPE { HOURLY, DAILY, MONTHLY };
    public static enum NATIONALITY { LOCAL, FOREIGN };
    @Required
    @Enumerated(EnumType.STRING)
    public TYPE type;
    @Required
    @Enumerated(EnumType.STRING)
    public NATIONALITY nationality;
}

And in my controller class I want to get list of EmployeeTypes using my 2 enum attributes.
Query looks like

Query query = JPA.em().createQuery("SELECT e FROM EmployeeType e where " +
            "e.nationality = :nationality " +
            "and e.type = :type");
query.setParameter("nationality", NATIONALITY.LOCAL);
query.setParameter("type", TYPE.HOURLY);

List<models.EmployeeType> employeeType = query.getResultList()

Gives this error: IllegalArgumentException occured : Parameter value [LOCAL] was not matching type [models.EmployeeType$NATIONALITY]

What should i do?

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  1. Editorial Team
    Editorial Team
    2026-06-18T07:58:10+00:00Added an answer on June 18, 2026 at 7:58 am

    The error is possibly because of the fact that your enums are nested in your entity. You need to access it on entity name.

    You can change your setParameter code to: –

    query.setParameter("nationality", EmployeeType.NATIONALITY.LOCAL);
    query.setParameter("type", EmployeeType.TYPE.HOURLY);
    
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