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Home/ Questions/Q 8312119
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T20:03:16+00:00 2026-06-08T20:03:16+00:00

I am working on setting up JqGrid with Grails and have in-line editing working.

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I am working on setting up JqGrid with Grails and have in-line editing working. I have a drop-down box appear when the user selects a specific cell.

I want to populate this drop-down list from a table but am having trouble connecting the pieces together. Here is the code i have so far…

$(document).ready(function() {

    jQuery("#task_list").jqGrid({
          ...

          colModel:[
          {name:'foo', editable:true, edittype:'select', editOptions:{values: ${com.project.inf.Domain.list()}}},
          ...

The ${com.project.inf.Domain.list()} creates a list of comma-delimited items, which I want to be displayed as options in the drop-down. However, it seems editOptions only accepts name:value pairs. Is there a simple way to re-format the List() so it is accepted?

Thanks for the help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T20:03:18+00:00Added an answer on June 8, 2026 at 8:03 pm

    After some experimentation and reading of tutorials, I found the solution to this problem. I had to create a custom controller action and use the “dataUrl” option to use it as follows:

    {name:'foo', width:100, editable:true, edittype:'select', 
    editoptions: {dataUrl:'${createLink(controller:"bar",action:"listAsSelect")}'}}
    

    With the following as the listAsSelect action in the “bar” controller:

    def listAsSelect={
        def lst = Bar.findAll()
    
        StringBuffer buf = new StringBuffer("<select>")
        lst.each{
            buf.append("<option value=\"${it.id}\">")
            buf.append(it.toString())
            buf.append("</option>")
        }
        buf.append("</select>")
    
        render buf.toString()
    }
    
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