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Home/ Questions/Q 8119417
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T04:47:50+00:00 2026-06-06T04:47:50+00:00

I am working out the months, days, hours and minutes between two dates, I

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I am working out the months, days, hours and minutes between two dates, I have successfully got it to work out the months, days and minutes, but I cannot for the life of get it to work out the minutes, below is my code.

<?php
    $date1 = "2012-07-01 00:00:00";
    $date2 = "2012-09-30 00:00:00";

    $diff = abs(strtotime($date2) - strtotime($date1));

    $years = floor($diff / (365*60*60*24));
    $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
    $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
    $minutes = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24) / (60*60*24) / (60*60));

    printf("%d years, %d months, %d days, %d minutes\n", $years, $months, $days, $minutes);

?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T04:47:52+00:00Added an answer on June 6, 2026 at 4:47 am

    The best and most accurate way to approach this problem is to use the DateTime class. Otherwise you’ll run into issues when you deal with anomalies in dates (leap year, etc).

    $format = 'Y-m-d h:i:s';
    $tz = new DateTimeZone('America/New_York');
    
    // Create DateTime objs based on the above format
    $t1 = DateTime::createFromFormat( $format, "2012-07-01 00:00:00", $tz);
    $t2 = DateTime::createFromFormat( $format, "2012-09-30 00:00:00", $tz);
    
    // Find the difference between them
    $diff = $t1->diff( $t2);
    
    // Print out the difference in each amount
    $outputs = array( 'Y' => 'Year', 'm' => 'Month', 'd' => 'day', 'h' => 'hour', 'i' => 'minute', 's' => 'seconds');
    
    foreach( $outputs as $key => $value)
        echo $diff->format( '%'.$key) . ' ' . $value . "\n";
    

    This outputs:

    00 Year
    2 Month
    29 day
    0 hour
    0 minute
    0 seconds
    
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