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Home/ Questions/Q 9166453
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T15:09:27+00:00 2026-06-17T15:09:27+00:00

i am working to get data by query string . i have done with

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i am working to get data by query string . i have done with httppost but not i am tring to get using httpget . but i am unable.

 List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
            nameValuePairs.add(new BasicNameValuePair("key", "android developer"));

            String k = "android developer";
             URI uri = new URI("http://10.0.2.2:8080/r/r.php");


             HttpClient httpclient = new DefaultHttpClient();
             HttpGet httpget = new HttpGet(uri);
             //httpget.setEntity(new UrlEncodedFormEntity(nameValuePairs));
             HttpResponse response = httpclient.execute(httpget);
             HttpEntity entity = response.getEntity();
             is = entity.getContent();

please expert help me

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T15:09:28+00:00Added an answer on June 17, 2026 at 3:09 pm

    You can do this via 2 ways:

    use a URI builder:

    new Uri.Builder()
        .scheme("http")
        .authority("foo.com")
        .path("someservlet")
        .appendQueryParameter("param1", foo)
        .appendQueryParameter("param2", bar)
        .build();
    

    create the url string yourself:

    String paramString = URLEncodedUtils.format(nameValuePairs, "utf-8");
    uri = new Uri("http://10.0.2.2:8080/r/r.php?" + paramString);
    
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