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Home/ Questions/Q 8312035
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T20:01:19+00:00 2026-06-08T20:01:19+00:00

I am working with a accordion which have gray scale images on load and

  • 0

I am working with a accordion which have gray scale images on load and on mouse over it images show in its real color.
Where is conflicting J query in my script..
Getting error : $ is not a function

<script type="text/javascript" src="js/jquery-1.4.3.min.js"></script>
<script type="text/javascript" src="js/kwicks.js"></script>
<script src="js/greyScale.js"></script>
<script>
$j = jQuery.noConflict();
$j(function () {
  $j('.greyScale').hide().fadeIn(1000); // fade in the grayscaled images to avoid visual jump
});
$j(window).load(function () {
  // user window.load to ensure images have been loaded
  $('.greyScale').greyScale({
    fadeTime: 500
    // call the plugin with non-defult fadeTime (default: 400ms)
  });
});
</script>
<script type="text/javascript">
$().ready(function () {
  $('.kwicks').kwicks({
    max: 535,
    spacing: 10,
    sticky: false
  });
});
</script>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T20:01:22+00:00Added an answer on June 8, 2026 at 8:01 pm

    Stick all of your script code in a closure like this:

    (function($) {
    
    ...
    
    }(jQuery));
    

    Then you can just use $ instead of $j and there will be no conflict.

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