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Home/ Questions/Q 8775667
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T18:51:46+00:00 2026-06-13T18:51:46+00:00

I am working with a function that would search for a substring in a

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I am working with a function that would search for a substring in a list of lists, as the first three characters of each item in the list. For example, if the substring is 'aaa' and the list of lists is [['aaa111', 'aba123', 'aaa123'], ['aaa302', 'cad222']], I would like the function to return a list of percentages [66, 50], since 'aaa' appears in the first list 2/3 times, and in the second list 1/2 times. So far I have:

def percentage(list_of_lists, substring):
    count = 0
    percentage = []
    for item in list_of_lists:
        for i in item:
            if substring == i[0:3]:
                count += 1
        percentage.append(int(count / len(item) * 100))
    return percentage

I understand that my code may be excessive, but I’m just getting the gist of Python so I’m not worried.

>>> percentage([['aaa111', 'aba123', 'aaa123'], ['aaa302', 'cad222']], 'aaa')
[66, 150]

How do I make it count list by list in my list_of_lists?

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  1. Editorial Team
    Editorial Team
    2026-06-13T18:51:48+00:00Added an answer on June 13, 2026 at 6:51 pm

    Two things…

    1. Reset your count for each loop
    2. Use float for division (only for python 2.x)

    I changed the count -> 0.0

    def percentage(list_of_lists, substring):
        percentage = []
        for item in list_of_lists:
            count = 0.0
            for i in item:
                if substring == i[0:3]:
                    count += 1
            percentage.append(int(count / len(item) * 100))
        return percentage
    
    # Test
    In [17]: l = [['aaa111', 'aba123', 'aaa123'], ['aaa302', 'cad222']]
    In [18]: s = 'aaa'
    In [19]: percentage(l,s)
    Out[19]: [66, 50]
    
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